bentuk aljabar[tex]Tentukan Pengurangan 10a - 9b-3c+5 oleh 5a - 10b + c +2[/tex][tex](x + 5) x (x + 9) =[/tex][tex](x³)5 =[/tex][tex](-3p²q³)² =[/tex]note:pake cara​

merlewolfulv – March 15, 2023

bentuk aljabar
[tex]Tentukan Pengurangan 10a - 9b-3c+5 oleh 5a - 10b + c +2[/tex]
[tex](x + 5) x (x + 9) =[/tex]
[tex](x³)5 =[/tex]
[tex](-3p²q³)² =[/tex]
note:pake cara​

Jawaban:

7p \times 7p = 49 {p}^{2}7p×7p=49p

2

10a \times 2b = 20ab10a×2b=20ab

( - 25m) \times ( - 2m) = 50 {m}^{2}(−25m)×(−2m)=50m

2

13ab \times 2b = 26a {b}^{2}13ab×2b=26ab

2

3(4 - 3y + 5) = 12 - 9y + 153(4−3y+5)=12−9y+15

3p(4pq + 5) = 12 {p}^{2} q + 15p3p(4pq+5)=12p

2

q+15p

- 2a(5a - 10b) = - 10 {a}^{2} + 20b−2a(5a−10b)=−10a

2

+20b

\begin{gathered}(2x - 5)(2x + 7) \\ = 4 {x}^{2} + 14x - 10x - 35 \\ = 4 {x}^{2} + 4x - 35\end{gathered}

(2x−5)(2x+7)

=4x

2

+14x−10x−35

=4x

2

+4x−35

\begin{gathered}(10x + 6)(2x + 7) \\ = 20 {x}^{2} + 70x + 12x + 42 \\ = 20 {x}^{2} + 82x + 42\end{gathered}

(10x+6)(2x+7)

=20x

2

+70x+12x+42

=20x

2

+82x+42

\begin{gathered}(x - 5)(2x - 10) \\ = 2 {x}^{2} - 10x - 10x + 50 \\ = 2 {x}^{2} - 20x + 50\end{gathered}

(x−5)(2x−10)

=2x

2

−10x−10x+50

=2x

2

−20x+50

Jawaban:

semoga bermanfaat

coba belajar lagi pemfaktoran sama eksponen